Explicit step-by-step computations using the standard recurrence relation for Bernoulli numbers.
For n >= 1:
B_n = -(1/(n+1)) sum(C(n+1, k) B_k, k=0 to n-1)
With B_0 = 1, B_1 = -1/2, and B_m = 0 for odd m > 1.
| n | B_n | Decimal |
|---|-----|---------|
| 0 | 1 | 1.0 |
| 1 | -1/2 | -0.5 |
| 2 | 1/6 | 0.1667 |
| 4 | -1/30 | -0.0333 |
| 6 | 1/42 | 0.0238 |
B_8 = -(1/9) sum(C(9,k)B_k, k=0 to 7)
Using known values (odd k>1 contribute 0):
Sum = C(9,0)1 + C(9,1)(-1/2) + C(9,2)(1/6) + C(9,4)(-1/30) + C(9,6)*(1/42)
= 1 - 9/2 + 36/6 + 126(-1/30) + 84(1/42)
= 1 - 4.5 + 6 - 4.2 + 2 = 3/10
B_8 = -(1/9) * (3/10) = -3/90 = -1/30
B_10 = -(1/11) sum(C(11,k)B_k, k=0 to 9)
Non-zero terms:
Sum with common denominator 6:
= (6 - 33 + 55 - 66 + 66 - 33)/6 = -5/6
B_10 = -(1/11) * (-5/6) = 5/66 = 5/66
B_12 = -(1/13) sum(C(13,k)B_k, k=0 to 11)
After evaluating all binomial coefficients and weighted sum:
Inner sum = 691/210
B_12 = -(1/13) * (691/210) = -691/2730 = -691/2730
Note: 691 is prime and does not divide 2730, so fraction is in lowest terms.
| n | B_n | Decimal |
|---|-----|---------|
| 0 | 1 | 1.0 |
| 1 | -1/2 | -0.5 |
| 2 | 1/6 | 0.16667 |
| 4 | -1/30 | -0.03333 |
| 6 | 1/42 | 0.02381 |
| 8 | -1/30 | -0.03333 |
| 10 | 5/66 | 0.07576 |
| 12 | -691/2730 | -0.25311 |
Even indices alternate sign. Magnitudes grow rapidly for larger indices.
Each B_{2k} generates a correction term in ln(n!):
| B_n | Stirling term | Coefficient |
|-----|--------------|-------------|
| B_2 = 1/6 | +1/(12n) | 1/12 |
| B_4 = -1/30 | -1/(360n^3) | -1/360 |
| B_6 = 1/42 | +1/(1260n^5) | 1/1260 |
| B_8 = -1/30 | -1/(1680n^7) | -1/1680 |
| B_10 = 5/66 | +1/(1188n^9) | 5/5940 |
| B_12 = -691/2730 | -691/(360360n^11) | -691/360360 |
These Bernoulli numbers support:
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